State whether the following rational number has a terminating decimal expansion or not. If it does,find it: $\frac{19}{256}$

(N/A) rational number $\frac{p}{q}$ has a terminating decimal expansion if the prime factorization of the denominator $q$ is of the form $2^n \times 5^m$,where $n$ and $m$ are non-negative integers.
Here,$q = 256 = 2^8$.
Since the denominator is of the form $2^n \times 5^m$ (where $n=8, m=0$),the rational number $\frac{19}{256}$ has a terminating decimal expansion.
To find the decimal expansion,we multiply the numerator and denominator by $5^8$:
$\frac{19}{2^8} \times \frac{5^8}{5^8} = \frac{19 \times 390625}{10^8} = \frac{7421875}{100000000} = 0.07421875$.